Fix using sizeof() for array given as function argument

When using the sizeof() operator for an array given as function argument it
returns the size of the pointer.
In this case, the affected function hex(char digest[16], char buff[33]) will
just print 4 or 8 byte instead of the full length of 16 bytes, on 32bit and
64bit systems respectively.

1 files changed, 1 insertions, 1 deletions

diff --git a/lib/erl_interface/src/connect/ei_connect.c b/lib/erl_interface/src/connect/ei_connect.c
index 6dc6ebb348..c24294fbd0 100644
--- a/lib/erl_interface/src/connect/ei_connect.c
+++ b/lib/erl_interface/src/connect/ei_connect.c
@@ -1197,7 +1197,7 @@ static char *hex(char digest[16], char buff[33])
     char *p = buff;
     int i;
     
-    for (i = 0; i < sizeof(digest); ++i) {
+    for (i = 0; i < 16; ++i) {
 	*p++ = tab[(int)((*d) >> 4)];
 	*p++ = tab[(int)((*d++) & 0xF)];
     }