diff options
| -rw-r--r-- | erts/emulator/beam/erl_bif_lists.c | 15 | ||||
| -rw-r--r-- | lib/stdlib/test/lists_SUITE.erl | 11 |
2 files changed, 25 insertions, 1 deletions
diff --git a/erts/emulator/beam/erl_bif_lists.c b/erts/emulator/beam/erl_bif_lists.c index aaf262780f..b69949f9cc 100644 --- a/erts/emulator/beam/erl_bif_lists.c +++ b/erts/emulator/beam/erl_bif_lists.c @@ -244,12 +244,25 @@ typedef struct { #define ERTS_RBT_GET_LEFT(T) ((T)->left) #define ERTS_RBT_SET_LEFT(T, L) ((T)->left = (L)) #define ERTS_RBT_GET_KEY(T) ((T)->key) -#define ERTS_RBT_CMP_KEYS(KX, KY) CMP_TERM(KX, KY) +#define ERTS_RBT_CMP_KEYS(KX, KY) subtract_term_cmp((KX), (KY)) #define ERTS_RBT_WANT_LOOKUP_INSERT #define ERTS_RBT_WANT_LOOKUP #define ERTS_RBT_WANT_DELETE #define ERTS_RBT_UNDEF +/* erl_rbtree expects comparisons to return an int */ +static int subtract_term_cmp(Eterm a, Eterm b) { + Sint res = CMP_TERM(a, b); + + if (res < 0) { + return -1; + } else if (res > 0) { + return 1; + } + + return 0; +} + #include "erl_rbtree.h" static int subtract_continue(Process *p, ErtsSubtractContext *context); diff --git a/lib/stdlib/test/lists_SUITE.erl b/lib/stdlib/test/lists_SUITE.erl index 984b51e7ae..9a0fe4b5ca 100644 --- a/lib/stdlib/test/lists_SUITE.erl +++ b/lib/stdlib/test/lists_SUITE.erl @@ -2586,6 +2586,15 @@ subtract(Config) when is_list(Config) -> [1,2,3,4,5,6,7,8,9,9999,10000,20,21,22] = sub(lists:seq(1, 10000)++[20,21,22], lists:seq(10, 9998)), + %% ERL-986; an integer overflow relating to term comparison + %% caused subtraction to be inconsistent. + Ids = [2985095936,47540628,135460048,1266126295,240535295, + 115724671,161800351,4187206564,4178142725,234897063, + 14773162,6662515191,133150693,378034895,1874402262, + 3507611978,22850922,415521280,253360400,71683243], + + [] = id(Ids) -- id(Ids), + %% Floats/integers. [42.0,42.0] = sub([42.0,42,42.0], [42,42,42]), [1,2,3,4,43.0] = sub([1,2,3,4,5,42.0,43.0], [42.0,5]), @@ -2613,6 +2622,8 @@ subtract(Config) when is_list(Config) -> ok. +id(I) -> I. + sub_non_matching(A, B) -> A = sub(A, B). |